Public Function ArithmeticShiftRight( _ ByVal vValue As Variant _ , ByVal vNBits As Variant _ ) As Variant
ArithmeticShiftRight( 128, 2) = 32 ArithmeticShiftRight(-128, 2) = -32 ArithmeticShiftRight(Chr$(128)) = Chr$(224) ArithmeticShiftRight(Chr$(0) + Chr$(128)) = Chr$(0) + Chr$(32) whereas ShiftRight( 128, 2) = 32 ShiftRight(-128, 2) = 16352 ShiftRight(Chr$(128)) = Chr$(32)See also:
ShiftRight Function RotateRight FunctionvValue: Value whose bits are to be shifted right arithmetically. Function returns Null if vValue is Null.
vNBits: The number of positions that the bits within vValue are to be shifted right. Function returns Null if vNBits is Null or cannot be fixed up to a number.
Function returns vValue unchanged if vNBits is 0 (zero).
Function returns Null if vNBits is < 0 (less than zero).
Function will return the same type of value as vValue, or in the case of Date values (in which not all combinations of bits are valid) it may possibly generate a runtime error.
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